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3c^2-36c+60=0
a = 3; b = -36; c = +60;
Δ = b2-4ac
Δ = -362-4·3·60
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-24}{2*3}=\frac{12}{6} =2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+24}{2*3}=\frac{60}{6} =10 $
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